(2pts) Given 750ml of an 5M Na2CO3 stock solution, how much do you need to make 675ml of a 25% Na2CO3 working solution

The answer is "256.33 ml".

Explanation:

Given

In solution means solution

 for solution mass of needed is calculated as

now calculating moles of the

by using the moles and molarity of the stock solution we calculate the volume of the stock solution:  

molarity = moles / volume in liter

so

convert liter to ml

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in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm