Calculate the percent yield of LiHCO3 if 58.0 g of CO2 produces 79.3 g of LiHCO3

On a Space shuttle, LiOH Is used to absorb CO2 to produce LiHCO3

LiOH + CO2 === LiHCO3

Now

58g of CO2 produces 79.3g of LiHCO3

This is the Actual Yield.

Recall

% Yield = Actual yield/Theoretical yield x100

NOW

We have to find the theoretical yield

From the equation of reaction

Now 58g of CO2 reacted

Converting to Moles

mole = Mass/Molar Mass

Molar mass of CO2=44g/mol

Mole = 58/44

=1.318moles of CO2

From the equation Of Reaction.

1 mole of CO2 reacts and Produces 1 mole of LiHCO3

Since their Mole ratio is 1:1

An Equal amount of LiHCO3 will be produced.

So 1.318moles of LiHCO3 will be produced.

Convert this mole to Mass

Mole =Mass/Molar Mass

Mass = Mole x Molar Mas

Molar Mass of LiHCO3 =68g/mol

Mass = 1.318 x 68

Mass = 89.62g.

This is the theoretical Yield.

% yield = 79.3/89.62 x 100

= 88.48%.

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.