3CaCl2 + 2AlF3 --> 3CaF2 + 2AlCl3 3CaCl2 + 2AlF3 --> 3CaF2 + 2AlCl3 How many grams of CaF2 will form from 36.5 grams of AlF3?

32.1 g

Explanation:

3CaCl₂ + 2AlF₃ → 3CaF₂ + 2AlCl₃

First we convert 36.5 g of AlF₃ into moles, using its molar mass:

36.5 g ÷ 133.34 g/mol = 0.274 mol AlF₃

Then we convert 0.274 moles of AlF₃ into moles of CaF₂, using the stoichiometric coefficients of the reaction:

0.274 mol AlF₃ * = 0.411 mol CaF₂

Finally we convert 0.411 moles of CaF₂ into grams, using its molar mass:

0.411 mol * 78.07 g/mol = 32.1 g

the answer to your question is c.

if you read the house of usher you should know that the house was haunted

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons