A mass of 21.5 grams of calcium hydroxide, Ca(OH)2 , reacts with an excess of phosphoric acid. 3 Ca(OH)2 + 2 H3PO4 --> Ca3(PO4)2 + 6 H2O How many moles of water would be produced? (MM of Ca(OH)2 is 74.1 g/mol)

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole