What is the balanced equation for the equilibrium reaction where the aqueous
bicarbonate ion, HCO3(aq); decomposes to
form hydrogen ions, H,
(aq), and carbonate
ions, CO2 ?

A balanced equation for the  equilibrium reaction where the aqueous bicarbonate ion, ; decomposes to  form hydrogen ions, and carbonate ions, is .

Explanation:

A balanced chemical equation is defined as the equation which contains same number of atoms on both reactant and product side.

Hence, balanced equation for the  equilibrium reaction where the aqueous bicarbonate ion, ; decomposes to  form hydrogen ions, and carbonate ions, is as follows.

Here, number of atoms present on reactant side are as follows.

Number of atoms present on product side are as follows.

Since, there are same number of atoms present  on both reactant and product side. Therefore, this equation is balanced.

Thus, we can conclude that balanced equation for the  equilibrium reaction where the aqueous bicarbonate ion, ; decomposes to  form hydrogen ions, and carbonate ions, is .

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%