A 59.0 mL portion of a 1.80 M solution is diluted to a total volume of 258 mL. A 129 mL portion of that solution is diluted by adding 183 mL of water. What is the final concentration

0.170 M

Explanation:

As this is a series of dilutions, we can continuosly use the C₁V₁=C₂V₂ formula to solve this problem:

For the first step:

Then for when 129 mL of that 0.412 M are diluted by adding 183 mL of water:

Using C₁V₁=C₂V₂:

true

explanation: