How do I calculate the pOH of a Solution at 25℃ with a [OH-1] = 6.5 x 10-9 M and state whether the Solution is Acidic, Basic, or Neutral?

pOH = 8.19

Acidic solution (pH < 7.0)

Explanation:

The pOH of the solution is defined as:

pOH = - log [OH⁻]

Since we have [OH⁻] = 6.5 x 10⁻⁹ M, we calculate the pOH as follows:

pOH = - log (6.5 x 10⁻⁹) = 8.19

To know if the solution is acidic, neutral or basic, we have to calculate the pH from the value of pOH:

pH + pOH = 14

⇒ pH = 14 - pOH = 14 - 8.19 = 5.81

The solution is acidic because pH < 7.0.

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