What is the volume of 1.60 grams of O2 gas at STP? 1.72 liters 1.45 liters 1.32 liters 1.12 liters

The required volume is 1.12 L.

Explanation:

Given,

Mass of O2 gas= 1.60 grams

We know,

Number of moles = Mass/Molecular mass

                             = 1.60/32                     [Molecular mass of O2 gas is 32 gram]

                             = 0.05

Again,

We know that at STP,

Number of moles = Volume in L / 22.4 L

or, Volume = Number of moles X 22.4

or, Volume = 0.05 X 22.4

or, Volume = 1.12

∴The required volume is 1.12 L.

the answer is the first option

explanation:

just googled it m8. not that hard

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