A mixture of 0.119 g of boron trifluoride (BF3) gas and 0.007 g of hydrogen sulfide (H2S) gas is held in a 1.74 L vessel at 19.24 ∘C. What are the mole fractions of the individual gases?

molar mass BF3 = 67.805 g/mole

molar mass CO2 = 44.009 g/mole

moles BF3 present = 13.5 g x 1 mole/67.805 g = 0.1991 moles

moles CO2 present = 12.8 g x 1 mole/44.009 g = 0.2908 moles

TOTAL moles present = 0.1991 + 0.2908 = 0.4899 moles

Mole fraction BF3 = 0.1991/0.4899 = 0.406 (to 3 sig. figs.)

Mole fraction CO2 = 0.2908/0.4899 = 0.594 (to 3 sig. figs.)

your parents i think this could be it

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates