Water is added to 215 mL of a 2.1 M solution of CaCl2 to increase the volume of the solution to 350. mL. What is the new concentration?

1.29 M

Explanation:

since it's a dilution, the new concentration must be less than 2.1 M

c1V1 = c2V2

c2 = c1V1/V2 = (2.1 M×215 mL)/350 mL = 1.29 M

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm