Calculate the molar mass of Ca3(PO4)2

934.32 g Ca3(PO4)2 =
moles Ca3(PO4)2

Molar mass of Ca₃(PO₄)₂ = 310.18 g/mol934.32 g Ca₃(PO₄)₂ = 3.01 moles Ca₃(PO₄)₂

Explanation:

The molar mass (MM) of Ca₃(PO₄)₂ can be calculated as follows:

MM of Ca₃(PO₄)₂ = (MM of Ca)*3 + [(MM of P) +(MM of O)*4]*2MM of Ca₃(PO₄)₂ = 310.18 g/mol

Now we can convert 934.32 g of Ca₃(PO₄)₂ into moles:

934.32 g ÷ 310.18 g/mol = 3.01 moles

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The closer the atoms are to becoming ionic the more highly dense the negatively charged side gets.