What is the mole fraction of KCI in an aqueous solution that contains
26.3% KCI (weight/weight %)?

The mole fraction is the number of moles of something divided by the number of total moles present. First, let us work out the number of moles of KCl present. A 26.3% w/w solution would contain 26.3 g of KCl per 100 g of solution. Hence, 26.3 g of KCl is 26.374.5513 = 0.353 moles

Explanation:

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consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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