If 50mL of 0.15M calcium sulfide is added to 30mL of 0.35M ammonium carbonate, how many grams of precipitate will form

0.750 g

Explanation:

The reaction that takes place is:

First we calculate how many moles of each reactant were added, using the given volumes and concentrations:

Given that they react in a 1:1 ratio, and that there are less CaS moles than (NH₄)₂CO₃ moles, CaS is the limiting reactant.

We now convert 7.5 mmol CaCO₃ into mg, using its molar mass:

Finally we convert 750 mg to g:

the dissolution of polymer can be thermodynamically described in 2 steps.