How many moles of KCl are produce when 61.5 g of KClO3 are decomposed?

0.502mol

Explanation:

The balanced chemical equation of the reaction described in this question is as follows:

2KClO3 → 2KCl+ 3O2

According to the equation above, 2 moles of KClO3 will produce 2 moles of KCl.

Using mole = mass/molar mass to convert mass of KClO3 to moles

Molar mass of KClO3 = 39 + 35.5 + 16(3)

= 39 + 35.5 + 48

= 122.5g/mol

mole = 61.5 g ÷ 122.5g/mol

mole = 0.502mol

Since 2 moles of KClO3 will decompose to produce 2 moles of KCl.

0.502 mol of KClO3 will decompose to produce 0.502 × 2/2

= 0.502mol of KCl.

idk i’m struggling too