7.34g of metal A changes in temperature from 41.4°C to 54.7°C and absorbs 923.5J in the process. Calculate the specific heat of metal A

9.46 J/g °C

Chemistry

Thermodynamics

Specific Heat Formula: q = mcΔT

Math

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step 1: Define

Identify variables

[Given] m = 7.34 g

[Given] q = 923.5 J

[Given] ΔT = 54.7 °C - 41.4 °C = 13.3 °C

[Solve] c

Step 2: Solve for c

Step 3: Check

Follow sig fig rules and round. We are given 3 sig figs as our lowest.

9.45966 J/g °C ≈ 9.46 J/g °C

Topic: AP Chemistry

Unit: Thermodynamics

Book: Pearson AP Chemistry

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