Ross attempted to titrate 30.0 mL of NaOH solution with 1.0 M HCl solution. The flask of NaOH solution contained 0.00300 mole of NaOH. Ross carelessly added 5.0 mL of HCl solution to the NaOH and observed blue litmus paper in the flask turn pink. What was the hydrogen ion concentration in the flask after all the HCl was added? A) 6.7 × 10-2 mol/L

B) 5.7 × 10-2 mol/L

C) 2.0 × 10-3 mol/L

D)1.0 × 10-7 mol/L

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

- aluminum and copper chloride.

- the chloride ion to separate the aluminum from the oxygen so that the aluminum can react with the copper ions (and the water molecules).

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).

um i think it might be a car?