How many atoms of Neon are in 65.0 L of Neon gas?

65.0 g NH3 x

mol NH3

17.04 g NH3

x  

6.02x1023 NH3 molecules

mol NH3

= 2.30x1024 NH3 molecules

(have uh good day)

mole of Neon = 65L/22.4L

=2.901moles of Neon

1 mole of a substance contains 6.022x10^23atoms

So 2.901moles will contains

2.901 x 6.022x10^23atoms

=1.747 x 10^24atoms

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !