How does changing the species of gas particle from heavy to light change the results of this exercise? Play with the sim a little. Make the lid pop off. How did you do it?
Make the lid pop off A DIFFERENT WAY. How did you do it?
Summarize the relationship between volume, temperature and pressure (use words like "inversely
proportional" or "directly proportionar). Use sentences.
We did not fully explore the relationship between moles and temperature, moles and volume or moles
and pressure. Can you design an experiment to show the relationship between moles and any one of the
other quantities? Give steps to follow to explore this here.

It's a

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

In any atom of any element, you will find protons and neutrons in the nucleus of any atom