Chemistry, 24.05.2021 16:10 marianesabrinap20

On the basis of stoichiometry, justify why 1 mL of 0.025M of Na2S2O3 is equivalent to 1.0 mg/L of DO? Calculate the DO value if your 250 mL sample consumes 18 mL of 0.014M Na2S2O3.

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On the basis of stoichiometry, justify why 1 mL of 0.025M of Na2S2O3 is equivalent to 1.0 mg/L of DO...

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