The equilibrium constant, Kp, for the following reaction is 0.636 at 600K. COCl2(g) <=> CO(g) + Cl2(g)

If an equilibrium mixture of the three gases in a 16.9 L container at 600K contains COCl2 at a pressure of 0.836 atm and CO at a pressure of 0.551 atm, the equilibrium partial pressure of Cl2 is atm.

The equilibrium partial pressure of is 0.964 atm.

Explanation:

Given:

The given reaction equation is as follows.

Formula used to calculate the partial pressure of is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that the equilibrium partial pressure of is 0.964 atm.

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation:

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j