1. Write the balanced reaction of Al with CuCl2. 2. What is the limiting reagent if 0.5 g Al is reacted with 3.5 g CuCl2? (Reminder: CuCl2 is a dihydrate)

3. What is the theoretical yield of copper produced by the reaction above?

help plsss

1.

2. CuCl₂·2H₂O is limiting reactant.

Chemical reaction: 3CuCl₂·2H₂O + 2Al → 3Cu + 2AlCl₃ + 6H₂O. m(Al) = 0,5 g.

3. The molar mass of copper is 63.546 grams per mole.

If we multiply everything out, we'll get 0.50722 grams of copper, which is our theoretical yield.

Hope it helps uh :)♡~

1 a

2 d

3 a

4 c

explanation:

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"