If I have 18 liters of gas at a pressure of 88 atm, what will be the final pressure of the gas if the volume of the gas is decreased to 12 liters under constant pressure ? Show calculations.

 You meant in constant temperature?

Because temperature is not mentioned at the beginning.

I suppose temperature remains constant, otherwise

there is no enough data for solving the problem

Explanation: According Boyle´s law in constant temperature

pV = constant.  So p1V1 = p2V2   and pressure p2 = p1V1 /V2

= 88 atm · 18 l / 12 l =  132 atm.

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