In an acid-base titration, a student uses 25.62 mL of 0.100 M HCl to reach the endpoint. How many moles of acid is this? A)2.56 x 10-1 ml HCl
B)2.56 x 10-3 mol HCl
C)2.56 x 10-2 mol HCl

Number of mole in HCL = 2.56 x 10⁻³ mol HCL

Explanation:

Given:

Volume of HCL = 25.62 ml

Molarity of HCL = 0.1 M

Find;

Number of mole in HCL

Computation:

Volume of HCL = 25.62 ml

Volume of HCL (in liter) = 25.62 / 1000

Volume of HCL (in liter) = 0.02562 L

Number of mole = Molarity x volume in liter

Number of mole in HCL = Volume of HCL (in liter) x Molarity of HCL

Number of mole in HCL = 0.02562 x 0.1

Number of mole in HCL = 0.002562

Number of mole in HCL = 2.56 x 10⁻³ mol HCL

b.false that your answer