Chemistry, 21.05.2021 03:30 zitterkoph
Two metals (Metal A and Metal B) are both exposed to a laser which emits photons that have a greater energy than the work function of both metals. Metal A has a smaller work function than Metal B. Therefore, The de Broglie wavelength of the electrons produced from metal A will be those from metal B. The number of electrons produced from metal A will be the number produced from metal B.
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Two metals (Metal A and Metal B) are both exposed to a laser which emits photons that have a greater...
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