Chemistry, 19.05.2021 19:10 hailey5129
Solid potassium sulfide is slowly added to 150 mL of a copper(II) chloride solution until the concentration of sulfide ion is 0.0464 M. The maximum amount of copper(II) ion remaining in solution is ___ M
Answers: 3
![K_{s p}=\left[\mathrm{Cu}^{2+}\right]\left[\mathrm{s}^{2-}\right]](/tpl/images/1334/2626/df925.png)
"
![\left[\mathrm{Cu}^{2+}\right]](/tpl/images/1334/2626/4270c.png)
"$. The concentration of sulfide ions is !["\left[\mathrm{~s}^{2-}\right]^{\prime \prime}](/tpl/images/1334/2626/f9fd3.png)
is 
![8 \times 10^{-37} &=\left[\mathrm{Cu}^{2+}\right] \times 0.0464](/tpl/images/1334/2626/f64f6.png)
![\left[\mathrm{Cu}^{2+}\right] &=\frac{8 \times 10^{-37}}{0.0464}](/tpl/images/1334/2626/9f9e3.png)
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Solid potassium sulfide is slowly added to 150 mL of a copper(II) chloride solution until the concen...
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