What will the volume be of a soltuion created using 120 ml of 4.5 M stock solution if the final molarity needs to be 2.00 M

We need 540 mmoles of stock solution and complete to 270 mL of volume.

Explanation:

In order to determine the volume or concentration at diluted solution we apply this formula:

Dil volume . Dil concentration = Conc volume . Conc concentration

Stock solution is always, the concentrated.

Let's replace with data given:

Dil. volume . 2 M = 120 mL . 4.5 M

Diluted volume = (120 mL . 4.5M)  / 2M

Diluted volume = 270 mL

This problem can be also solved by rule of three:

1 mL of stock solution contains 4.5 mmoles

120 mL of stock solution contain (120 mL . 4.5 mmoles) / 1mL = 540 mmoles

This mmoles of stock solution are also contained at the diluted

If 2 mmoles are contained in 1mL of diluted solution

540 mmoles must be contained in (540 mmol . 1 mL) / 2 mmol = 270 mL

We need 540 mmoles of stock solution and complete to 270 mL of volume.

tracks, burrows, eggshells, nests, tooth marks, or gastroliths

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.