Calculate the solubility in mol/L of Lead(II) carbonate (PbCO3) at 298 K. Ksp = 7.4 x 10-14
02.7 107 mol/L
O 7.2 x 10-7 mol/L
o 3.5 x 10-4 mol/L
02.7 x 10 5 mol/L
o 7.4 x 10-7 mol/L

2.7x10⁻⁷mol/L

Explanation:

Based on the equilbrium:

PbCO₃(s) ⇄ Pb²⁺(aq) + CO₃²⁻(aq)

The solubility product, Ksp, is defined as:

Ksp = 7.4x10⁻¹⁴ = [Pb²⁺] [CO₃²⁻]

Now, solubility is defined as the amount of PbCO₃ that is dissolved, that is the concentration of the ions. Thus:

Solubility = S = [Pb²⁺] = [CO₃²⁻]

Replacing:

7.4x10⁻¹⁴ = [S] [S]

7.4x10⁻¹⁴ = [S]²

S = 2.7x10⁻⁷mol/L

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.