At 304 K, a 9.6 L tank contains 1.9 moles of H2 gas under an unknown pressure in atm. What is the pressure of the gas in the tank? (R = 0.0821 L*atm/mol*K)

The pressure is 4.939 atm

Explanation:

As we know

PV = nRT

where P is the pressure

V is the volume

n is the total number of moles

R is the gas constant

and T is the temperature

Substituting the given values we get -

The pressure is 4.939 atm

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied