In the reaction Pb + 2Ag+ – Pb2+ + 2Ag, the Ag+ is. a) reduced, and the oxidation number changes from +1 to 0.
b)reduces and the oxidation number changes from +2 to 0.
c)oxidized and the oxidation number changes from 0 to +1.
d) oxidized, and the oxidation number changes from +1 to 0.
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Question :-

In the reaction Pb + 2Ag+ – Pb2+ + 2Ag, the Ag+ is.

a) Reduced, and the oxidation number changes from +1 to 0.

b) Reduces and the oxidation number changes from +2 to 0.

c) Oxidized and the oxidation number changes from 0 to +1.

d) Oxidized, and the oxidation number changes from +1 to 0.

Solution :-Given Information :-Reaction ➢ Pb + 2Ag⁺ ⟶ Pb²⁺ + 2Ag To Find :-Whether Ag⁺ is:-a) Reduced, and the oxidation number changes from +1 to 0.b) Reduces and the oxidation number changes from +2 to 0.c) Oxidized and the oxidation number changes from 0 to +1.d) Oxidized, and the oxidation number changes from +1 to 0.Answer :-

Firstly let us know the meaning of Oxidation & Reduction and Oxidizing & Reducing Agent :-

Oxidation is process of loss of electron(s). Either atom or ion undergoing oxidation, is known as reducing agent.Reduction is process of gain of electron(s). Either atom or ion undergoing reduction, is known as oxidizing agent.

In this reaction, Ag⁺ gains an electron to get reduced to Ag. The oxidation number changes from +1 to 0. Therefore, Ag+ is an oxidizing agent.

Since, this possibility is given in option a). Reduced, and the oxidation number changes from +1 to 0. Hence, option a is the correct answer.

Final Answer :-Option a. Reduced, and the oxidation number changes from +1 to 0 is correct answer.

Ethene molecular fórmula= c2h4molecular weight = 29.046g/molhope it : )

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