NaCl+AgNO3–>AgCl+NaNO3 If 45g of salt reacts with sliver nitrate what mass of sliver chloride will be produced?

45g of NaCl x 1mole of NaCl/58.5g

= 0.769moles of Nacl

Now Looking at the equation

1mole of Nacl produces 1mole of AgCl

so

0.769mole of NaCl will produces the same Mole of AgCl(0.769)

So the Moles of AgCl produced = 0.769

Recall

Mole = Mass /Molar Mass

Mass = Mole x Molar Mass

Molar Mass of AgCl =108 + 35.5 = 143.5

Mass of Agcl = 0.769 x 143.5

=110.35g of AgCl

m = 4.2gAgCl

Explanation:

c (diamond),

sio2 (quartz)

because of all the things that happen around the us, many people get into arguments which sadly could get physical, but we should actually make a change for that.