How much energy will be released when 600g of steam at 100⁰C is condensed to water at 100⁰C ?

Answer

53.6 KJ

Explanation:

The energy released came from two discrete processes: the steam condenses to release some latent heat of condensation at  100 l o C the water cools down to  0 l o C  to  100 l o C  without solidfying. The amount of energy released in the first process is dependent on the  L v  latent heat of vaporization for water and the mass of the sample: E ( phase change ) = m ⋅ L v = 20 l g × 2 , 260 l J ⋅ g − 1  E ( phase change ) = 45 , 200 l J On the other hand, the amount of energy released in the second process depends on both the specific heat of water, the mass of the sample, and the magnitude of the change in temperature. E ( cooling ) = m ⋅ c ⋅ Δ T  E ( cooling ) = 20 l g ⋅ 4.2 l J ⋅ g − 1 ⋅ K − 1 ⋅ ( 100 l K − 0 l K )  E ( cooling ) = 8 , 400 l J  Taking the sum of the energy change of the two processes gives the total amount of energy released: E ( released ) = E ( phase change ) + E ( cooling ) = 53 , 600 l J = 53.6 l kJ

its going to be mutualism cuz they both benefit from the relationship.

~batmans wife dun dun

c.

explanation: