Studying the decay of radioactive isotopes in dead organisms helps scientists to identify fossilized remains. The ratio of C-12 to C-14 in the atmosphere is 1 x 1012. The table shows this ratio inside the body of three organisms. C12/C14 Ratio
Organism C12/C14 Ratio
E 8 x 1012
F 1 x 1012
G 4 x 1012

What can most likely be concluded from the above information?
Only Organism F is alive, and Organism G died before Organism E.
Only Organism F is alive, and Organism E died before Organism G.
Only Organism E is alive, and Organism G died before Organism F.
Only Organism E is alive, and Organism F died before Organism G.

answer; economic order quantity;

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2