Hydrogen sulfide gas can be produced from the reaction of aluminum sulfide and water according to the following equation: Al2S3(s) 6H2O(l) > 3 H2S(g) 2Al(OH)3(aq) What volume of hydrogen sulfide gas is produced if 65.0 g Al2S3 reacts at 90.0 oC and 0.987 atm,

The volume of hydrogen sulfide gas is 38.8 L.

Explanation:

The given reaction equation is as follows.

Mass of is given as 65.0 g. Hence, moles of (molar mass = 150.158 g/mol) is calculated as follows.

As 1 moles of is giving 3 moles of . Hence, moles of formed by 0.433 moles of are as follows.

Here, pressure is 0.987 atm and temperature is . Therefore, volume of hydrogen sulfide is calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

Thus, we can conclude that volume of hydrogen sulfide gas is 38.8 L.