The specific heat capacity of liquid water is 4.18 J/g oC. Calculate the quantity of energy required to heat 1.50 g of water from 26.5oC to 83.7oC. (Ignore significant figures for this problem.)

The quantity of heat required is 358.644 J.

Explanation:

Given: Specific heat capacity =

Mass = 1.50 g

Formula used to calculate heat energy is as follows.

where,

q = heat energy

m = mass

C = specific heat capacity

= initial temperature

= final temperature

Substitute the values into above formula as follows.

Thus, we can conclude that quantity of heat required is 358.644 J.