B. Calculate The number of moles of hydrochloric acid in 10 mL of 6.0 M HCI; 6,0 M HCl contains 6 moles of HCI per liter of solution.

hydrochloric acid has a molar mass of

36.46 g/mol

, which means that the

164-g

sample will contain

164

g

⋅

1 mole HCl

36.46

g

=

4.498 moles HCl

As you know, molarity is defined as moles of solute, which in this case is hydrochloric acid, divided by liters of solution

molarity

=

moles of solute

liters of solution

A

6.0-M

hydrochloric acid solution will contain

6

moles of hydrochloric acid for every liter of solution. This means that

4.498

moles will come with a volume of

c

=

n

V

⇒

V

=

n

c

V

=

4.498

moles

6.0

moles

L

=

0.7497 L

idk

explanation: