What is the pOH of a 3.0 x10-3 M NaOH solution?
pOH =

2.5

Explanation:

From the question given above, the following data were obtained:

Molarity of NaOH = 3.0x10¯³ M

pOH =?

Next, we shall determine the concentration of the hydroxide ion in the solution. This can be obtained as follow:

NaOH (aq) —> Na⁺ (aq) + OH¯ (aq)

From the balanced equation above,

1 mole of NaOH produced 1 mole of OH¯.

Therefore, 3.0x10¯³ M NaOH will also produce 3.0x10¯³ M OH¯.

Finally, we shall determine the pOH of the solution. This can be obtained as illustrated below:

Concentration of hydroxide ion [OH¯] = 3.0x10¯³ M

pOH =?

pOH = – Log [OH¯]

pOH = – Log 3.0x10¯³

pOH = 2.5

Thus, the pOH of the solution is 2.5

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.