A 45.2 g sample of Silver at 101.0 ºC is dropped into 300.0 g of water at 30.6 ºC. What is the final temperature of the water?

Final temperature of water = 31.2° C

Explanation:

Let the final temperature of water be T degrees

Concept: By energy conservation law

Heat lost by the silver = heat gained by water

Heat lost be silver Q1 = m1c1ΔT1

Q1 = 45.2/1000Kg×2.36J/KgK×(101-T)

Heat gained by water Q2 = m2c2ΔT2

Q2 = 300/1000Kg×4.186J/KgK(T-30.6)

Since, Q1=Q2

⇒  45.2/1000Kg×2.36J/KgK×(101-T) = 300/1000Kg×4.186J/KgK(T-30.6)

Solving we get T = 31.2° C

Therefore, final temperature of water = 31.2° C

yes, water is wet, just as it makes other things wet, it is wet itself, kinda like ice, when ice is in water, the ice makes water cold, and ice is cold, therefore with that example, water is wet

the volume increases