How many atoms are in 5.9 g of N2?

Number of atoms in 5.9 g of N2 = 1.268 *10^23

Explanation:

Weight of one mole of N2 is 28.0134 g

In one mole of N2, number of atoms = 6.023 *10^23

Number of atoms in 28.0134 g (one mole) of N2 =  6.023 *10^23

Number of atoms in 1 g of N2 = 6.023 *10^23/28.0134

Number of atoms in 5.9 g of N2 = 6.023 *10^23/28.0134 * 5.9

= 1.268 *10^23

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c. orbital shape i hope this is correct