In 2Fe+3Cl2=2FeCl3, how much iron (Fe) is needed to produce 4 moles of FeCl3? In 2Fe+3Cl2=2FeCl3, how much FeCl3 is produced when 5 moles of Fe react in excess chlorine?​

4 mol Fe

5 mol FeCl₃

Explanation:

Step 1: Write the balanced equation

2 Fe + 3 Cl₂ ⇒ 2 FeCl₃

Step 2: Calculate how much iron (Fe) is needed to produce 4 moles of FeCl₃

According to the balanced equation, the molar ratio of Fe to FeCl₃ is 2:2.

4 mol FeCl₃ × 2 mol Fe/2 mol FeCl₃ = 4 mol Fe

Step 3: Calculate how much FeCl₃ is produced when 5 moles of Fe react in excess chlorine

According to the balanced equation, the molar ratio of Fe to FeCl₃ is 2:2.

5 mol Fe × 2 mol FeCl₃/2 mol Fe = 5 mol FeCl₃

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it is stable as it is in group 0 which have full outer shells of electrons