Chemistry, 06.05.2021 22:30 colochaortiz20p7cajw
Pd(NO₃)₂ + NaCl ---> PdCl₂ + NaNO₃
140 grams of lead (II) nitrate (Pd(NO₃)₂) are dissolved in water then mixed with a solution containing 75 grams of sodium chloride (NaCl). The reaction creates the precipitate, lead (II) Chloride (PdCl₂), and a solution of sodium nitrate (NaNO₃) . How many grams of lead (II) Chloride can be produced given the initial amount of lead (II) nitrate?
Stoichometry based.
All I need is the set up, but you can give answer if you want.
Please help.
Answers: 3
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Pd(NO₃)₂ + NaCl ---> PdCl₂ + NaNO₃
140 grams of lead (II) nitrate (Pd(NO₃)₂) are dissolved in w...
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