Calculate the molar concentration of a solution containing 3.0 moles of NaCl in 325 milliliters of water.

The molarity of the solution is 0.617 M.

Explanation:

Let's use this equation:

Okay, so we have a bit of work to do! The volume is given in terms of mL and we have to convert that to L by using the following conversion factor:

1

L

=

1000

m

L

350

mL

×

1

L

1000

mL

=

0.350

L

Now we have to express NaCl in terms of moles. We can do this by using the molar mass of NaCl (58.44 g/mol) as a conversion factor.

12.6

g

×

1

m

o

l

58.44

g

=

0.216

m

o

l

Now we can divide the moles by the volume to obtain the molarity like this:

M

o

l

a

r

i

t

y

=

0.216

m

o

l

0.350

L

M =0.617Explanation:

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

- "the choice that is not an indicator of a chemical change is "state of matter changes". more common than not, chemical reactions produce energy in the form of light or heat. along with energy, they also produce a new substance called the product that could be in any state of matter (solid, gas, or liquid)."