The formation of tin IV chloride is as follows; the change in enthalpy is (AH) is -511 kJ/mole. Sn (s) + 2 C12 (9) --> SnC14 (1) + Heat
The reaction would be considered?
A. Endothermic, releases heat
B. Exothermic, release heat
C. Endothermic, absorbs heat
D. Exothemric, absorbs heat

Select the correct value for the indicated bond angle in each of the compounds. o−o−oo−o−o angle of o3 90° 109.5° < 109.5° 120° < 120° 180° f−b−ff−b−f angle of bf3 180° < 109.5° < 120° 120° 109.5° 90° f−o−ff−o−f angle of of2 < 120° 120° 90° 109.5° 180° < 109.5° cl−be−clcl−be−cl angle of becl2 90° 109.5° 180° 120° < 109.5° < 120° f−p−ff−p−f angle of pf3 90° 109.5° < 109.5° 180° 120° < 120° h−c−hh−c−h angle of ch4 90° < 109.5° 180° 120° < 120° 109.5°