Now you shine light with a continuous energy distribution and you observe absorption lines at the following photon energies: 1eV, 3eV, 4eV, and 7eV. Using the information from the two experiments described, select the energies that correspond to all the energy levels of this atom. Hint: Similar to potential energy, the absolute values of the energy levels are arbitrary to a constant, but the difference in energies between levels is not. Follow the convention that the ground state energy (the lowest energy state) is the negative of the ionization energy and base your other answers around this. O eV
-1 eV
-2 eV
-3 eV
-4 eV
-5 eV
-6 eV
-7 eV
-8 eV
-9 eV
-10 eV
-11 eV
-12 eV
Now you turn off the light and run a beam of electrons through the gas. The kinetic energy of the electrons is 3.5 eV. Collisions of the electrons in the beam with the atoms in the gas exite the atoms to states above the ground state. Select all the possible energies of the emitted photons from this gas.
1 eV
2 eV
3 eV
4 eV
5 eV
6 eV
7 eV
8 eV
9 eV
10 eV

Maybe you should get some from your teacher and learn more so you can get your grades up and maybe study a bit more

  remember that hf is only the energy of one photon. not two. not three. one.  1) 5.12 * 10^3 photons  find the energy of one photon, then determine how many photons are needed to reach the sensitivity.  e = hf  = (6.626 * 10^-34 js)(5.95 * 10^19 hz)  = 3.94247 * 10^-14 j per photon  (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons  round to three sig figs.  2) 5.77 * 10^-17 j  energy of pulse = energy per photon * number of photons  = hfn  = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250)  = 5.774559 * 10^-17 j  round to three sig figs.  3) 4.07 * 10^8 kj/mol  10^12 pm = 1 m  c = fλ  f = c/λ  e = hf  = hc/λ  = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol)  = 40702571.4 kj/mol  round to three sig figs.  4) 9.94 * 10^-1 m  e = hc/λ  λ = hc / e  = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j)  = 0.9939 m  round to three sig figs.  5) 9.06 * 10^3 photons  energy of pulse = energy per photon * number of photons  number of photons = energy of pulse / energy per photon  = energy of pulse / (hf)  = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)]  = 9055.23695 photons  round to three sig figs.  6) 2.78 * 10^-15 j  this is problem 1, except in reverse.  sensitivity = minumum number of photons * energy per photon  = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz)  = 2.78070758 × 10^-15 j  round to three sig figs.

The molar mass of a substance is defined as the mass of 1 mol of that substance, expressed in grams per mole, and is equal to the mass of 6.022 × 10 23 atoms, molecules, or formula units of that substance.