Pick the larger species from each of the following pairs. a. When comparing the two species Pd and Pd2+ the larger of the two is
b. When comparing the two species Se^2- and Sr^2+ the larger of the two is
c. When comparing the two species Sr and Sr^2+ the larger of the two is
d. When comparing the two species N and N^3- the larger of the two is

1. Sr^2+
2. Se^2-
3. Pd^2+
4. Pd
5. Sr^2+
6. N^3-
7. N^3-
N
Sr

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

elements

explanation:

yes the other ones are right just show me a pic of ur face cuz u look hot

i think   the answer is c hope i'm right