2 Na + Cl2 --> 2 NaCl If 15 mol Na reacts with 15 mol Cl2 , what is the theoretical yield of NaCl that could
be formed?

Determine the limiting reagent

Using the stoichiometric ratios from the balanced reaction equation the mole ratio of Na : NaCl = 2 : 2.

The moles of NaCl produced by 15 moles of Na can be obtained as follows.

M

o

l

e

s

o

f

N

a

C

l

=

2

m

o

l

N

a

C

l

2

m

o

l

N

a

×

15

m

o

l

N

a

=

15

m

o

l

e

s

Using the stoichiometric ratios from the balanced reaction equation the mole ratio of

C

l

2

: NaCl = 1 : 2.

The moles of NaCl produced by 15 moles of

C

l

2

can be obtained as follows.

M

o

l

e

s

o

f

N

a

C

l

=

2

m

o

l

N

a

C

l

1

m

o

l

C

l

2

×

15

m

o

l

C

l

2

=

30

m

o

l

e

s

Since the moles of NaCl produced by Na is less than the moles produced by

C

l

2

, Na is the limiting reagent.

The theoretical yield of NaCl = Moles of NaCl produced by the limiting reagent =

15

m

o

l

Explanation:

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

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