What is the molality of a solution of Al(C103), in water that boils at 103.82°C (K) = 0.512°C/m)?

Because the freezing point of pure water is 0°C, the sucrose solution freezes at ... where K b is the molal boiling point constant and m is the concentration of the solute ... Calculate the total ionic molality of a solution of 50.0 grams of aluminum.

Explanation:

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"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"