If 57.5 mol of an ideal gas is at 4.97 atm at 69.80 ∘C, what is the volume of the gas?

325 L

Explanation:

We will use the ideal gas law: PV= nRT. Let's rearrange it so we're solving for V, so it'll instead be V=

Before we start, let's check our units. Usually it has to be the same as the units found in the constant (R)= 0.082057 L⋅atm/mol⋅K. We have temperature in Celsius here so let's convert it to Kelvin (K).

69.80C +273= 342.8 K

Now we can plug everything in.

V=

V== 325 L

5.6⋅10−^19  j

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