Use the masses of the elements below to calculate the mass of 8.70 moles of H3M (the number at the bottom of each square is the atomic mass of that element)
1
2
3
4
5
6
A
H
C
B
M
Sm
aragon
hillsdale
capuchino
mills
burlingame
san mateo
1.10
3.50
7.09
11.22
15.23
18.98
Given:
Wanted
Relationship: 1 mole H3M =
grams
Final answer
grams

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.

points

explanation: