GeF3H is formed from GeH4 and GeF4in the combination reaction: GeH4 + 3GeF4 → 4GeF3H If the reaction yield is 83%, how many moles of GeF4are needed to produce 8.00 mol of GeF3H?

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.

5.6⋅10−^19  j

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