Section 1.7 showed that in 1997 los angeles county air had carbon monoxide (co) levels of 15.0 ppm. an average human inhales about 0.50 l of air per breath and takes about 20 breaths per minute. part a how many milligrams of carbon monoxide does the average person inhale in an 6 hour period for this level of carbon monoxide pollution? assume that the carbon monoxide has a density of 1.2 g/l. (hint: 15.0 ppm co means 15.0 lco per 106l air.)

First, let's determine the amount of air a human intakes per minute:

0.5 L/breath * (20 breaths/min) = 10 L/min

So, for 6 hours, the amount of volume would be:

6 hrs = 360 min
10 L/min ( 360 min = 3,600 L of total air inhaled

Next, we convert the concentration to g/L. The solution is as follows:
15 L CO/10⁶ L air * 1.2 g CO/L = 18 g CO/L air
So, we multiply to this the volume of air inhaled.

Amount of CO inhaled = (18 g CO/L air)(3,600 L of total air)(1,000 mg/1 g)
Amount of CO inhaled = 64.8×10⁶ mg of CO inhaled

Ans. : frostbite is when exposure to cold temperatures causes freezing to the skin or other tissues. it most commonly affects the hands, feet, and face. the longer areas are exposed to cold, typically the worse the frostbite. the water temperature used for rewarming a frostbitten part should be : (102 -105) f degrees.